I have some tables like this: Employee: Teams: TeamMember: I am trying to get list of employees with info regarding who they are : Team Member or Team Leader or Individual. Current output: Expected output: Query: Only issue here is that I am getting TeamId and TeamName as blank for “Team Leader” data as shown below: Current output: Can anyone
Tag: left-join
MySQL – category with product count not showing all results
I am trying to display the count of products along with the category name in the category list. I was able to achieve this with JOIN, but not all categories are displayed. I mean the categories with 0 products were not displayed, but I changed the JOIN to LEFT JOIN which displayed only one category with 0 products. There are
SQL: JOIN vs LEFT OUTER JOIN?
I have multiple SQL queries that look similar where one uses JOIN and another LEFT OUTER JOIN. I played around with SQL and found that it the same results are returned. The codebase uses JOIN and LEFT OUTER JOIN interchangeably. While LEFT JOIN seems to be interchangeable with LEFT OUTER JOIN, I cannot I cannot seem to find any information
Count from 4 tables with join and null values
Tables: What I am expecting to query is this: However this is what I get: With this query: I wonder, in what way the query above could be modified to return the expected results? What would be a good approach to achieve this? Answer You are joining along two dimensions, so you are getting a Cartesian products. That is simply
SQL: Use LEAD() and PARTITION BY to access to the next row following the current row
I have a mobile app browsing history dataset as shown below. DeviceDateTime: Date and Time the User views the page in the mobile app. UserID: each UserID represents a visitor who login the mobile app. PageName: There are different pages in the Mobile App. All visitors would first land on the Home page, and then navigate to different pages. PageSequence:
Adding a calculated column while joining tables in Snowflake
I have 4 tables A, B, C and D with 3 columns each A- aa, ab, ac B- ba, bb, bc C- ca, cb, cc D- da, db, dc I need to join the 4 tables and add a new calculated column (aa + ab + ac). My query …
MySQL tree structure
Hello i am trying to prepare tree structure with MySql, tables look something like this. My Question is: Is it possible to do left join and sort columns by name, but if in lang is eq to “fra” return that row with that name, otherwise return “eng” name. Pseudo code So final result will be something like this, in total
How to display the total count of the last row by filestatus?
I have to display the total count of the last row by filestatus. tbl_bankdata tbl_fileStatus I have two tables tbl_bankdata and tbl_fileStatus. I am sending bank_id in the tbl_fileStatus as a f_bank_id. Now I have to show the last f_bankid count. For example, I have to fetch the count where f_filestatus=1. so my output will be 0. Why 0 because
Return in which or statement results are from SQL [closed]
Closed. This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 1 year ago. Improve this question I’m having the following SQL statement, to return worksheets that teachers have liked, and worksheets that teachers made by themselves. It’s working fine, but now
Getting sum of two rows in an inner joined table
I have these two tables; trips id date revenue 1 01/01/2020 5000 2 01/01/2020 3000 3 02/01/2020 4000 4 02/01/2020 2000 expenses id tripid amount 1 1 500 2 1 300 3 2 400 4 2 200 5 2 700 I would like to get the sum of revenue collected in a day AND sum of expenses in a day.