Replace NULL values per partition

I want to fill NULL values in device column for each session_id with an associated non-NULL value. How can I achieve that? Here is the sample data: +————+——-+———+ | session_id | step …

Using columns in window function that are not in Group By, I get : SQL compilation error: [COLUMN_A] is not a valid group by expression

I’ve seen a lot of questions about this error, the closest one (as it’s using window function) to my issue would be this one My issue is that I use columns in the windows function that are not …

Wrong syntax for OVER and PARTITION in MySQL syntax

SELECT Id, Price, CustomerId, ROW_NUMBER() OVER (PARTITION BY CustomerId) FROM Orders; I get the error “Syntax error: Unexpected ‘(‘ (opening parenthesis) Does MySQL not support this? I’m pretty …

SQL: Expression Not in GROUP BY Key

I have a transaction table t1 in Hive that looks like this: store_id cust_id zip_code transaction_count spend 1000 100 123 3 50 2000 200 …

If ID has both values A and B it should return AB

INPUT: ID VALUES 1 A 1 B 2 A 3 B OUTPUT: ID VALUES 1 AB 1 AB 2 A 3 B If ID has both values A and B it should return AB.

Assign new value to every unique number in SQL Server

I am new to SQL Server and trying to do some operations Sample data: Amount | BillID ——-+——- 500 | 10009 500 | 1492 350 | 15892 222 | 15596 899 | 20566 350 | 9566 How can …

window functions and grouping – how to propagate data from row 1 through row 3 in a partition?

I have this query below: select Contact.IndividualID, Contact.IndividualID as ContactId, Contact.CaseNumber as CaseID, [Case].ProgramCode as Benefit, Contact.Email as EmailAddress, …

How to capture first row in a grouping and subsequent rows that are each a minimum of 15 days apart?

Assume a given insurance will only pay for the same patient visiting the same doctor once in 15 days. If the patient comes once, twice, or twenty times within those 15 days to the doctor, the doctor …

Auto increment temporary column in select statement MySQL 8

Hello i use this type of sentence to return an auto increment column in my prepared statement selects cnt := cnt + 1 SET @query = CONCAT(‘SELECT * FROM (SELECT (@cnt := @cnt + 1) AS id, a….

Count distinct per fiscal year and display all dates in query result

DB-Fiddle: CREATE TABLE customers ( id int auto_increment primary key, order_date DATE, customerID VARCHAR(255) ); INSERT INTO customers (order_date, customerID ) VALUES (“2020-01-…