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Select query to show missing values per day as 0

I have one table with product id’s and another with daily data for these products. When there is no data I want to return 0 instead of no value at all. I tried using a left join but this doesn’t give the resultset I want since the table I can join on has product id’s only, not per day. I

MySql Select Statement (Other Company)

I am trying to select distinct users that are listed for other companies but not on my company (1). Here is an example From this table, I would like to get row 4 since he is in other company (not 1) but listed on others. I do not want others because they are listed on both my company and others.

Increase the value of a column

I want create a CTE or something that subtract a know value from a sum() of value. How can I solve this, I tried to use LAG() on my CTE but it faulted when my value is negative. This is what I tried to do: This is the result of the query And this is what I expect from the

Select distinct columns for which all rows meet a condition

I want to select the distinct a, b’s for which all the c’s have a specific value (in my case null) So given the rows below the result should be I have failed to successfully translate that to a query, could you please help me out? Answer Try: where bool_and is a postgres aggregate function. Or may…

Using classes from /target

I am using JOOQ. JOOQ generates meta classes, using with database requests. It’s recommended to generate classes into /target/generated-sources/jooq. But when I try to call these meta classes in code, they are not accessible. Please, tell me what to do. Answer This is the default output location because…