I would like to update (divide the value by 100) in table wp_postmeta column meta_value where meta_key = price_cents eg. My code: UPDATE wp_postmeta SET meta_value = meta_value / 100 WHERE meta_key = price_cents; Above SQL statemant gives me error: #1054 – Unknown column ‘price_cents’ in …
Tag: mysql
SQL how do I sum up a has many relationship
So I have the following table, I managed to join users and membership tables just fine with a left join however I’ve been unsuccessful at summing up the individual customers’ total. Here’s my code, the one-to-one associations seem to be doing fine however the summing up of the total seems to…
How to select from two selected tables in Laravel Query Builder?
I want to convert my SQL to Laravel Query Builder version, however I can’t do that. Can anyone help me to solve this case or give me some advices, thank you. Original SQL that work fine in mysql server. Converted the original SQL to Laravel Query Builder, but it doesn’t work. Error: SQLSTATE[42S02…
mysql return people with similar purchase and desc order by count of similar items
customers table id name 1 a 2 b 3 c 4 d purchase table product_id customer_id x 1 y 1 x 4 y 4 x 3 z 2 the customer table has customer data and purchase table has order data. Now coming to question, I want customers id who bought similar products ordered by the count of similar items eg:
MySql using interval with a list of dates
I’m willing to fetch all the dates that are listed in the list reducing 1 day I’m trying something like that: I wish to receive: ‘2022-03-21’, ‘2022-03-17’, ‘2022-03-10’ Answer It can be done with intervals. Here is a link to how it works : https://www.db-fiddle…
SQL CASE WHEN won’t meet condition
This is a solution to one of the leetcode problem. It is asking me to output the second highest salary from the table and if there are no second highest salary then the output should be null. The above is my solution. I used case and when syntax but the problem is that even when the table only has 1
How to select a query from mysql database based on a certain condition
I want to answer the following question using the below Mysql tables. How many days were the user active on avg. (had an action) in the last week? I want to Display user Avg by day, where ((user action is not 0)/unique day) in the last 7 days. 0 means the user is not active and 1 means active. I
MySql query to return a random row returns unexpected number of rows
I am trying to get a random word from a long list of words in a MySql table: word_list [id*|wword]. My query looks at the moment like this: SELECT * FROM word_list w where id = (SELECT FLOOR(1 + RAND()*(10-1))) I thought the above query would return one and only one random row with Id between 1 and 9. To
Need guidance on MySQL Query
I am having a table with values like this below one. Col1 Col2 Col3 Col4 col5 1 John ABC 10 20 1 John AED 52 15 1 John ABC 12 10 1 John AED 20 5 1 John ABC 10 5 2 Mark DDD 42 8 2 Mark BBB 10 5 3 Ben EEE 8 2 3 Ben FFF 1
All values from first column matching values in second column as well as not matching values from second column
userColumn permissionColumn user1 permission1 user1 permission2 user2 permission1 user3 permission1 user3 permission3 user4 permission1 As cited in the subject line, I need to fetch all those users who have permissions ‘permission1’ but at the same time, I have to make sure that it doesn’t h…