I have 2 tables – Dates and Data with data as follows: Table: Dates Table: Data Expected results: I have tried using PARTITION OVER but getting duplicate vales and not all dates from Dates table, therefore not getting desired results. Really appreciate if you can help with the code in Hive SQL. Answer Use a cross join to generate the
Tag: hive
Using Case WHEN to extract with first character
I am using case as an if else statement in my hive database, it seems it is not showing what i am trying to extract as. i am using this script in logical concept if at character 44 starts with _ , substring at 45 , else substring at 45 e.g (table look like ) am i using like statement
HIVE SQL: Select rows whose values contain string in a column
I want to select rows whose values contain a string in a column. For example, I want to select all rows whose values contain a string ‘123’ in the column ‘app’. table: result: I am not familiar with SQL query. Could anyone help me? . Thanks in advances. Answer In a number of ways: like: rlike: instr: locate: Invent your
Hive throwing ParseException while exporting a csv
Running this code, I am trying to export a csv but I get the following error: ParseException line 2:3 cannot recognize input near ‘MIN’ ‘(‘ ‘HIGH’ in expression specification Answer Try to add table alias (d) and use select d.* instead of select *:
Using row_number update column value using previous row value
I have a table in hive contents are below Now I want to update the to_d column where row_num > 1 using some conditions like below Please don’t get me wrong I am just trying to help one of the other user’s question Updating column values based on the other table values in hive tables I was trying this approach
Hive – How to read a column from a table which is of type list
I have a Hive table named customer, which has a column named cust_id of list type, with following values: cust_id Now I want to read only this specific column cust_id in my select query, which can give all these list values as following separate values of this column cust_id: Basically I want to fetch all the values of cust_id from
Hive – Split and count values by delimiter – lateral view explode
I have a following Hive table I need to split and get the count values of each item in item_val column Expected output I tired below count but values are not getting delimited properly. Please help! Answer In Hive, one option is to use the lateral view syntax:
Hive nested query left join
I’am new to hive and i want to implement the following query It works fine untill the last left join. Nested queries are obviously not authorized in hive. How can i approach this. Answer Use sub-query instead of joined table: Or better move last join condition inside the WHERE clause in the subquery:
Impala: Split single row into multiple rows based on Date and time
I want to split a single row into multiple rows based on time. Expected output is below: Day start from 00:00 AM to next day 00:00 AM. When EndDate time is greater than 00:00 AM (midnight) then split this date in two rows. First row end date is 30/03/2020 11:59:00 and next row start 31/03/2020 00:00:00. Please help me to
HIVE-SQL_SERVER: HadoopExecutionException: Not enough columns in this line
I have a hive table with the following structure and data: Table structure: Trying to push this data into the SQL Server. But while doing so, getting the following error message: What I tried: There’s an online article where the author has documented similar kind of issues. I tried to implement one of them Looked in Excel and found two