I am using SQL server to select this table and group the customer id and first name according to their total payments made to the store. I tried using but it returns the following error: not contained in either an aggregate function or the GROUP BY clause Could you please clarify what I did wrong? this is my customer table
Tag: group-by
How to filter inconsistent records in sqlite
Say I have SQLite table with the following records: recID productID productName 1 1 Product A 2 2 Product B 3 2 Product C 4 3 Product D 5 3 Product D recID = primary key, auto increment. If I run: Result is: productID productName 1 Product A 2 Product B 2 Product C 3 Product D As you can
MySQL ignore NULL Value while using LAG() function
I want to calculate the MonthByMonth difference of payments happening throughout the year. For example, if I had 100 payments in February & 120 in the month of March, the difference would be 20. I have already made a query that uses LAG(), but the only problem I’m facing is that the query is showing NULL Value. Since there are
Is it possible to change the value of a column if it has more than one result (using GROUP BY)?
Is it possible to change the result only if there’s more than one? My query brings this result: Date Code Description Amount 01/01 1001 Produt A 1234 02/01 1001 Produt A 2345 03/01 1001 Produt A 3456 If I have only one produt, that’s fine. But if I have more than one, it shows like this: Date Code Description Amount
Making a MySQL COUNT query
after 4 days of tries and researchs over the web I can’t make my wishes working. Any help would be appreciated ! Performed on MYSQL WORKBENCH I got a DB made of 3 tables : user Posts likes username id id id title userId (foreign key from user.id) email content postId (foreign key from posts.id) password date image imageUrl userId
SQL: How to combine values in column week (i.e. week 1, week 2, etc) into week range (week 1-2 or week 1, 2)?
General SQL question using online SQLite editor, if I have the following table: item week sales item1 1 35 item2 1 25 item3 1 24 item1 2 35 item2 2 34 item1 3 24 item2 3 45 item1 4 44 item2 4 51 item1 5 1 item3 5 100 how would I get the output to be this: item weeks
There are duplicate records in table, we need to select only the latest records as per date using group by or window function in sql
There are duplicate records in table, we need to select only the latest records as per date using group by or window function in sql code: Answer You can simply use a GROUP BY like so If you want to use ROW_NUMBER you have to PARTITION BY the id
Can I get the full rows when using group by multiple columns?
If the date, item, and category are the same in the table, I’d like to treat it as the same row and return n rows out of them(ex: if n is 3, then limit 0, 3). expected results (if n is 3) The problem is that I have to bring the values of each group as well. If I have
Postgres – Pick 1 max row instead of all max rows in the same month on a LOD (group by)
Hi have a data set which has product, site, station, date and some numerical fields such as sn_count, blob etc. Within every combination of product, site and station, if there are multiple entries for the same month from different dates, I want to only pick one row with max sn count in that month. The code I have right now
How to output every combination of values in 2 columns, in groups? – SQL
I have a table where I want every parent to be mapped to every child within each group. Input: Output: So within each group, I want every value in parent to map to every value in child. If there are no values in child for a group, I want that group completely omitted (as shown where group_id = 3) I