This should be easy, maybe even a duplicate, but neither my brain nor my search engine is being very helpful today. My problem is as below: Given two tables that both have: A start date A stop date A property of an employee. Let’s say Desk Number in table A and Team in table B The employee’s unique ID number.
Tag: date
How to return 14th day from month which was 2 months ago with determinated time in Oracle SQL?
How can I take the 14th day from month which was 2 months ago with time 23:59:59 in Oracle SQL ? I have query like below and I need answer something like below (similar style): Above query return: 21/12/31, nevertheless I need query like above which will return value: ’21/12/14 23:59:59′ Answer You can use: Which outputs: DAY 2021-12-14 23:59:59
Grouping based on start date matching the previous row’s end date SQL
Hoping someone can help me out with this problem. I have the following sample dataset: MEM_ID CLM_ID ADM_DT DCHG_DT 1 111 01-01-2020 02-01-2020 1 112 03-01-2020 04-01-2020 1 113 04-01-2020 05-01-2020 1 114 06-01-2020 07-01-2020 2 211 01-01-2020 02-01-2020 2 212 05-01-2020 08-01-2020 3 311 02-01-2020 03-01-2020 3 312 03-01-2020 05-01-2020 3 313 05-01-2020 06-01-2020 3 314 07-01-2020 08-01-2020 I
Oracle SQL : how to specify Time Zone Region
Underlined, as hours are not specified, that means that hour is ’00:00′ I would like to specify that this is for Europe/Paris time zone region. Can you help me set-up this ? Thanks Answer A DATE data type has the components: year, month, day, hour, minute and second. It ALWAYS has those components and NEVER stores anything else (such as
SQL return rows on or after an specific date
I am trying to export a list of member details that have an expiry date after 2019 so I am just after I thought I could simply use the date in a WHERE clause However, it still returns the other entries and not sure why Answer Assuming that you are using SQL Server: dbfiddle
Create column with timeframe relative to other column in SQL
Suppose I have the following table t_1 where every row represents a day: How can I create the following table t2 from t1? Here val_cur is defined as the sum of values of the current timeframe (i.e. the sum of values between date_start and date_end) and val_prev is defined as the sum of values of the previous timeframe (i.e. the
Merging Respective Start and End Dates, Setting Flag Depending on Start/End Date – SQL
Problem: I have a table of transactions (see below) with either (open/start) or (close/end) transaction in the format of date. The task is to merge these transactions with their corresponding dates, however, there can be also cases when the transaction is opened/started, but not closed/ended, in which case only Start Date must be shown, and the Flag ‘Y’ assigned. The
How to dynamically pass in a date_or_time_part for DateDiff?
I have a column with strings such as “month” and “year” in it, but when I pass that into the first argument for datediff it fails saying: [‘COLUMN_NAME’] is not a valid date/time component for function DATEDIFF. How can I pass in column_name as the first argument to datediff as a date_or_time_part so that it can dynamically set the time
Use one of two dates in where clause
I need to delete all records in a table where the CreatedDate or ModifiedDate is greater than x. The logic is as follows: If ModifiedDate is not null then use this value Otherwise use the CreatedDate value Not applying the if/else statement correctly. Answer Use this where clause:
Why is the return type of sysdate DATE? [closed]
Closed. This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 9 months ago. Improve this question Sysdate returns the current system date and time and its return type is of date. But shouldn’t date type only contain