two table EMPLOYEE and Department EMPLOYEE’s fields are ID,Name, Salary ,DEPT_ID(foreign key to department table) DEPARTMENT’S fields are id,NAME,LOCATION VALUES OF EMPLOYEE TABLE WILL Be Values OF DEPARTMENT TABLE WILL BE Output from these table should be DEPARTMENT_Name should be alpabetically within their count If are there same Count DEPARTMENT_Name should appear in alpabetically and count will be desc order
Tag: mysql-workbench
MySQL:How to Rewrite a Select element as ‘y’ then using that later in a where statement
So what im trying to do is this but this doesn’t work: Here is another example: Answer You can’t use an aggregate expression (sum(), count(), …) in the where clause of the query. This clause is evaluated before rows are grouped together by the group by clause, so the aggregates are not yet available. In SQL, that’s the purpose of
Constant field has to be set MySQL
Attribute ‘Territory program’ is a constant field and has to be set to ‘Territory and Quota Program’ constant in result set, I don’t want to add a new column in table, so how can I do that in my select statement if possible? Also I have a column Status… not distributed – if data exists but not distributed to employee
How to format date that looks like this (20200326) MYSQL
I have two fields with dates in them. I am trying to format them to look like 03/26/2020 instead of 20200326. So far my code looks like this changed most of it due to my job guidelines so I can’t show you the exact code. Answer Use date_format():
issue with INNER JOIN in MYSQL 6.3
im trying to join data from two tables like this: Select portt.nameport, tool.weapen From Portt Where portt.toolsum – ( select count(*) From tool …
Symmetric Pair in SQL with JOIN
I am trying to find the name of students where a symmetric pair exists. There are 3 tables: Edit from your comment: A student is called as being a part of a symmetric pair if the marks obtained by that student in science is equal to the marks obtained by some other student in mathematics and the marks obtained in
MySQL Workbench reports “is not valid at this position for this server version” error
For the following SQL query: SELECT CONCAT( customers.name, ‘ ‘, customers.familyname ) As Name, I receive the following error message: “SELECT” is not valid at this position for this server …
SQL group by get latest results
My question is in the picture: SQL query
How do I keep my “validity” row always updated in relation to my “expiration date” row?
This is my database’s survey table: I learned to use CURDATE() and DATEADD(), so the table can now automatically calculate the survey_date and its expiration_date. But I’d also like to add a value …
MYSQL Procedure not getting called
The Following procedure after getting called, shows up error “The Result return more than one row” where the input value given is just one parameter. DELIMITER $$ CREATE PROCEDURE p( IN en …