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Tag: database

Partition by with condition statement

I have data of products that are sold by various shops. For some shops they are sold with discount mapped by PROMO_FLG. I would like to display two COUNT PARTITION columns. First displays all shops that thave this product (which is done) COUNT(DISTINCT STORE) OVER (PARTITION ITEM) would give is 10 Second one – which I seek – counts only

Flat file NoSQL solution [closed]

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers. We don’t allow questions seeking recommendations for books, tools, software libraries, and more. You can edit the question so it can be answered with facts and citations. Closed 2 years ago. The community reviewed whether to reopen this question 1 year ago and left it

SQL Multiple data input at the same time

there are 2 different queries below. How can I run them at the same time? I mean, these 2 data’s will be into on the same row. For example: https://prnt.sc/rtkytf Answer Doesn’t this do what you want? Otherwise, if you really want to insert four rows: The default value is often NULL (because no DEFAULT is specified). If you know

How to prevent including database config.php from another client?

We have this config.php file: And this structure The index file is accessable via www.example.com/index.php, but the config.php file too (via www.example.com/config.php). Can others just include www.example.com/config.php in there php files and execute code with my $conn? How to prevent this? Answer It’s true that if you leave files in the web root, the web server will execute them when

Find all users with a unique last name

I have a table users. I wrote a sql query that displays all users with a unique last name tell my why query removes collapsed users name2 and name3? HAVING COUNT(DISTINCT u.first_name) = 1; How it works? help to understand how it works Answer The query is aggregating by last name and counting the number of users. Run this version

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