I need to derive the “new” column from the “old” column using sql and regex if possible. I’m using Oracle SQL Developer. If I were using regex in R or Python, I would use this recipe to get the “new” column:
x
[1,2,3,4,5,6,7,8,9]{1,5}|b0b
old new
P003 3
4 4
P00005 5
P0005 5
12 12
P00000016 16
0 0
Thanks.
Use this:
REGEXP_SUBSTR(old, '[1-9]{1,9}0{0,10}|[1-9]{1,5}|b0b') as new
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Answer
Here’s one option:
SQL> with test (old) as
2 (select 'P003' from dual union all
3 select '4' from dual union all
4 select 'P00005' from dual union all
5 select 'P0005' from dual union all
6 select '12' from dual union all
7 select 'P00000016' from dual union all
8 select '0' from dual
9 )
10 select old, to_number(regexp_substr(old, 'd+')) new
11 from test;
OLD NEW
--------- ----------
P003 3
4 4
P00005 5
P0005 5
12 12
P00000016 16
0 0
7 rows selected.
SQL>