Write a query to find only those customers whose grade are, higher than every customer to the city New York Answer You can use MAX in your subquery instead: As @GordonLinoff points out, if there are no customers from New York, this query will fail. You can work around that by using COALESCE to convert the MAX value from NULL
Tag: mysql
id value needs a default value according to error 1364?
I want to create two tables. practice has a AUTO_INCREMENT attachment and is a PRIMARY KEY. continued has the id entity continued_id which exists as a FOREIGN KEY that references practice(user_id). Mysql executes the code below fine until line 19, where I receive the 1364 error, stating that continued_id has no default value. I am confused. I thought that user_id,
How to select count between start to (start+length) [closed]
Closed. This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 2 years ago. Improve this question How the following result appears when creating a table as above. This is the result of counting if the value is included between start plus
One if or multiple where?
Let’s say, I want to set a value to multiple rows depending on the value of another cell. So, I can make this in 2 ways: Select all items and set different values using IF: Update `table` set `a` = …
Condition’s speed in query [closed]
Closed. This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 3 years ago. Improve this question Given both give the same result and from the same data. Does adding the condition at SELECT (CASE WHEN) make
Sql select count use five condion
i count to some row form my database in five condition use the sql query it’s work with 0 if i put the number more than 0 then it not show any result. please help . it’s work with script $query33=…
MySQL query – addition, count and divide in one query
I have a table with column “Score”, which holds a number ranging from 1 to 10. I need to achieve the following calculation in MySQL: Column: Score Row 1: 10 Row 2: 9 Row 3: 9 Row 4: 7 Row 5: 10 …
GROUP_CONCAT to return an object array in a many to many relationship
I am working on a mySQL query for a personal project. Right now the end goal is to have the query return the following json for each item: My most recent attempt is: Which is giving me an internal server error. Testing it with a simplier query goes through fine so I’ve narrowed it down to the query itself being
How do i crack this SQL Soccer Matches assignment?
I came across this problem recently, i’m a sql newbie preparing for an interview and i need some help understanding how to connect the tables without using joins (since there is no common column)to …
Unknown column in field list when use join MySQL
I have 2 tables like this: product_master: campaign_product: This tables link with foreign key product_id I want to get all product data with campaign_code column. I don’t want to get 2 campaign_product row with same product_id. So I use this query: It got error when I run: Error in query (1054): Unknown column ‘dmspro_mys_campaign_product.campaign_code’ in ‘field list’ How I can