You are given a database of notebooks that contains two tables. the table notebooksbrand contains data about the name of notebook brands. the table notebooksnotebook contains data about the name of the notebook, its diagonal, width, depth, and height, and has a link to the brand to which this model belongs. You need to select groups of notebooks by size.
Tag: lateral-join
Snowflake cross join + lateral flatten
I have a semistructured column that I would like to left lateral join after a cross join. In the above, I would expect the original cross join to expand the result count from 1 to 3; and the left lateral join should not reduce the number of rows returned. The result I obtain is unexpected: COL A SEQ KEY PATH
Why does CROSS JOIN LATERAL break up array’s SDO_GEOMETRY object into individual attributes?
Oracle 18c: I have mapping software that has a limitation where it can only handle a single geometry column per table. If there are multiple geometry columns in a given table, then it will throw an error. So, I want to find a way to add an additional geometry column to a table, but store it as a datatype that
SQL – ordering table by information from multiple tables
Title of the question may not have been very clear – I am not really sure how to name this question, but I hope that my explanation will make my problem clearer. I have 3 tables: [1] score id rating_type 1 UPVOTE 2 UPVOTE 3 DOWNVOTE 4 UPVOTE 5 DOWNVOTE 6 DOWNVOTE [2] post_score post_id score_id 1 1 1 2
Grouping the result set based on conditions
I am calculating Age of a user based on his date of birth. This gives me the UserId and his age. Now I want to group this result. How many users are in 30’s, How many users in 40’s and how many users in their 50’s.. need the count of users with their age groups If the user is >
How can I unite these two related queries?
I have this query to check if a person is a customer or have been: And I have this other query to get the locations: How can I unite them and show person location as a single row on the first query? Answer If I follow this correctly, you can use lateral joins: As commented already, your original first query
Find closest match to value in another table
I have a table_a with many rows and columns for each timestamp in PostgreSQL 13. I’m trying to find the row where the value in column X is closest to a benchmark value obtained from another table. This second table has only a single benchmark value for each timestamp. For each timestamp, I need to return most of the columns
how can i check if value exists before the date specified in sql server
I have the data below in a sql table, let assume the user wants to get data of 2020-11-13 which is but i’d like to get the previous supplier due as well before the date specified which is along with so the actual query i wanna get is this and if there is no previous due i wanna return i
Create a PostgreSQL view from a unique list of exploded data
When I make this request: I get results like this: Each line has values separated with / (space, slash, space). How to create a view with a list of unique values with count ? Answer You can split the string to rows with regexp_split_to_table() in a lateral join, then aggregate: Demo on DB Fiddle: val | cnt :—- | –:
Postgres, split single row into multiple rows
I’ve got a table with columns like: I want to return: I ended out writing a large query using 3 unions like this, but this does not seem right: Is there a way to do this without the mess? Seems like I’m missing something really obvious. Answer In Postgres, you can efficiently unpivot the columns to rows with a lateral