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How can I use select count (distinct x) in order to count two values in the same table and get the the two distinct values in my output?

I am trying to use count (distinct) in order to count the number of distinct values for two different values in the same table. The output I am trying to get should have both of the distinct values as two separate columns. I have been trying different methods but I keep on getting syntax errors. I am able to to count just one of the values without any problem, but I can not figure out the syntax for two.

For example, I can count one by executing:

But I want to do something along the lines of this:

And get two output values as two separate columns.

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Answer

Can’t you just have two expressions in the select?

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