I have a problem. I heve data frame 1 named “df”:
And I have the data frame 2 named “dfP1”:
I want to compare the unique rows that exist in colum “Campo a Validar” from “dfP1” vs the columns in “df”, if exist a coincidence that count the number of nulls in the colum that match. And then the number of nulls will insert in the data frame df into a new colum name “Numeros_de_nulos” but only in the row 0 (index 0).
Here is something that tried:
x
#Validacion de Regla 1
if pd.isnull(df["Nº Línea Cliente"]).values.ravel().sum() > 0:
nulos = pd.isnull(df["Nº Línea Cliente"]).values.ravel().sum()
print("Hay {} valores nulos".format(nulos))
dfP1['Numeros_de_Nulos'] = None
else:
print ("No hay valores nulos")
dfP1.head()
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Answer
It was a bit challenging to determine what you needed, but this might come close to your ideal solution.
import pandas as pd
from numpy import NaN
# Assuming that these dictionaries accurately reflect
# your DataFrames's contents, then the
# following might work:
_df = {
"c1": [1.0, 3.0, 5.0, 7.0],
"c2": [1.0, 3.0, 5.0, 7.0],
"c3": [1.0, 3.0, 5.0, 7.0],
"c4": [1.0, 3.0, 5.0, 7.0],
"Nº Línea Cliente": [
"Hay algo",
"Hay algo",
"Hay algo",
NaN],
"c6": [1.0, 3.0, 5.0, 7.0],
"c7": [1.0, 3.0, 5.0, 7.0],
"c8": [1.0, 3.0, 5.0, 7.0],
"c9": [1.0, 3.0, 5.0, 7.0],
"c10": [1.0, 3.0, 5.0, 7.0],
}
Campo_a_Validar = [
"Nº Línea Cliente"
for campo in range(4)]
Campo_a_Validar.append("TIPO DE GARANTIA 1")
_dfP1 = {
"ID_Val": [1,2,3,4,5],
"Tipo_Validación": [1, 2, 3, 4, 1],
"Campo_a_Validar": Campo_a_Validar,
}
# Initializing the DataFrames
df = pd.DataFrame(_df)
dfP1 = pd.DataFrame(_dfP1)
def analizar_para_nulos(_df_, _dfP1_):
try:
contar_nulos = lambda DF, ColName: DF.groupby([ColName])[ColName].nunique()
nulos_de_df = contar_nulos(_df_, "Nº Línea Cliente")
nulos_de_dfP1 = contar_nulos(_dfP1_, "Campo_a_Validar")
assert(
nulos_de_df.values[0] == nulos_de_dfP1.values[0]
)
num_nulos = nulos_de_df
return num_nulos.values[0]
except AssertionError:
return 0
# Check whether the number of unique rows is
# equal to the number of unique rows in
# the other table
is_coincidence = analizar_para_nulos(df, dfP1)
if is_coincidence:
base = [is_coincidence]
base.extend([""
for position in range(len(df.c1) - 1)])
num_columns = len(df.T)
df.insert(
loc=num_columns,
column="Numeros_de_Nulos",
value=base
)
print(df)
else:
print(df)
Output:
c1 c2 c3 c4 Nº Línea Cliente c6 c7 c8 c9 c10 Numeros_de_Nulos
0 1.0 1.0 1.0 1.0 Hay algo 1.0 1.0 1.0 1.0 1.0 1
1 3.0 3.0 3.0 3.0 Hay algo 3.0 3.0 3.0 3.0 3.0
2 5.0 5.0 5.0 5.0 Hay algo 5.0 5.0 5.0 5.0 5.0
3 7.0 7.0 7.0 7.0 NaN 7.0 7.0 7.0 7.0 7.0