I have a database (Postgres 7.4) field for address
Example Data
address | zip -----------------------+-------------+ 123 main street | 12345 -----------------------+-------------+ 3 where road | 12345 -----------------------+-------------+ South 3 where road | 12345
The queries
SELECT * FROM tbl WHERE zip = 12345 AND address ILIKE '3%'
I get all but I don’t want 123 main street
SELECT * FROM tbl WHERE zip = 12345 AND address ILIKE '123%'
I get the results I want
My question is how do I just match the numeric part of the address?
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Answer
SELECT substring(address, '^\d+') AS heading_number FROM tbl WHERE zip = 12345 AND address ILIKE '3%'
Returns 1 or more digits from the start of the string.
Leave out the anchor ^
if you want the first sequence of digits in the string instead of the sequence at the start. Example:
SELECT substring('South 13rd street 3452435 foo', '\d+');
Read about substring()
and regular expressions in the manual.
In more recent versions (8.0+, with standard_conforming_strings = on
), use escape string syntax like this:
SELECT substring('South 13rd street 3452435 foo', E'\d+');
Or just:
SELECT substring('South 13rd street 3452435 foo', 'd+');