SQL query GROUP BY groups

I have something like this:

id	name	totalAmount
1	name1	10
2	name1	20
3	name1	25
4	name2	5
5	name2	12

And need to looks like this:

id’s	name	totalAmount
1,2	name1	30
2,3	name1	45
1,3	name1	35
1,2,3	name1	55
4,5	name2	17

I’m using the STRING_AGG but don’t know how to separated in the first 3 id’s.

Answer

Here is a recursive version which can handle more than 3 ids for a name and returns all possible combinations. As Dai points out though, take care as the number of combinations quickly mushrooms. But if your real data is like your example (normally 2-3 ids per name) than it should be fine.

Worth noting that I did this for fun. Probably you would be best just storing the raw data and doing this kind of shenanigans in the application layer.

CREATE TABLE #data
(
    id INT,
    [name] VARCHAR(10),
    totalAmount INT 
);
INSERT INTO #data
VALUES 
(1, 'name1', 10),
(2, 'name1', 20),
(3, 'name1', 25),
(4, 'name2', 5),
(5, 'name2', 12);

WITH cte (name, ids, maxid, tot) AS
(
    SELECT a.name, 
        CONVERT(VARCHAR(8000), CONVERT(VARCHAR(10), a.id) + ',' + CONVERT(VARCHAR(10), b.id) ) AS ids, 
        b.id AS maxid,
        a.totalAmount + b.totalAmount AS tot
    FROM #data a
    INNER JOIN #data b ON b.name = a.name AND a.id < b.id
    UNION ALL
    SELECT cte.name,
        CONVERT(VARCHAR(8000), cte.ids + ',' +CONVERT(VARCHAR(10), a.id)), 
        a.id AS maxid,
        cte.tot + a.totalAmount
    FROM cte
    INNER JOIN #data a ON cte.name = a.name
    WHERE a.id > cte.maxid
)
SELECT ids, name, tot
FROM cte