DB: postgres (PostgreSQL) 10.16 (Ubuntu 10.16-0ubuntu0.18.04.1)
I have a table device_clients in which following data is present:
| id | device_id | client_id |
|---|---|---|
| 1 | 1 | 1 |
| 2 | 2 | 1 |
| 3 | 3 | 1 |
| 4 | 4 | 1 |
| 5 | 5 | 1 |
| 6 | 6 | 1 |
| 7 | 7 | 1 |
| 8 | 8 | 1 |
| 9 | 1 | 2 |
| 10 | 1 | 3 |
| 11 | 1 | 4 |
| 12 | 2 | 2 |
| 13 | 2 | 3 |
| 14 | 2 | 4 |
| 15 | 3 | 2 |
| 16 | 3 | 3 |
| 17 | 3 | 4 |
I need to find out devices common between each client I provide. For e.g. following are the devices for each client
Client-1 => 1, 2, 3, 4, 5, 6, 7, 8 Client-2 => 1, 2, 3 Client-3 => 1, 2, 3 Client-4 => 1, 2, 3
So for clients 1, 2, 3 the common devices expected are 1, 2, 3.
Can anybody please help me formulate an efficient query to achieve the desired results?
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Answer
You can use aggregation. For instance:
select device_id from t where client_id in (1, 2, 3) group by device_id having count(*) = 3;
For convenience, you can pass the list of clients in as an array, allowing you to use:
select device_id from t where client_id = any(:client_ar) group by device_id having count(*) = cardinality(:client_ar)