SQL, extract everything before 5th comma

For example, my column “tags” have

"movie/spiderman,genre/action,movie:marvel", 
"movie/kingsman,genre/action",
"movie/spiderman,genre/action,movie:marvel,movie:dfjkl,movie:fskj,movie:aa,movie:mdkk"

I’m trying to return everything before 5th comma. below is the result example

"movie/spiderman,genre/action,movie:marvel", 
"movie/kingsman,genre/action",
"movie/spiderman,genre/action,movie:marvel,movie:dfjkl,movie:fskj"

I’ve tried below code but it’s not working.

select
NVL(SUBSTRING(tags, 1,REGEXP_INSTR(tags,',',1,5) -1),tags)
from myTable

Answer

You can use

REGEXP_REPLACE(tags, '^(([^,]*,){4}[^,]*).*', '\1')

See the regex demo.

The REGEXP_REPLACE will find the occurrence of the following pattern:

• ^ – start of string
• (([^,]*,){4}[^,]*) – Group 1 (1 refers to this part of the match): four sequences of any zero or more chars other than a comma and a comma, and then zero or more chars other than a comma
• .* – the rest of the string.

The 1 replacement restores Group 1 value in the resulting string.