The problem:
I have a table that records data rows in foo
. Each time the row is updated, a new row is inserted along with a revision number. The table looks like:
id rev field 1 1 test1 2 1 fsdfs 3 1 jfds 1 2 test2
Note that in the table the last record is a newer version of the first row.
Does anyone know of an efficient way to query for the latest version of the rows, ans a specific version of records? For instance, a query for rev=2
would return the 2, 3 and 4th row (not the replaced 1st row though) while a query for rev=1
yields those rows with rev <= 1 and in case of duplicated ids, the one with the higher revision number is chosen (record: 1, 2, 3).
I’m not actually sure if this is even possible in SQL Server…
I would not prefer to return the result in an iterative way.
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Answer
To get only latest revisions:
SELECT * from t t1 WHERE t1.rev = (SELECT max(rev) FROM t t2 WHERE t2.id = t1.id)
To get a specific revision, in this case 1 (and if an item doesn’t have the revision yet the next smallest revision):
SELECT * from foo t1 WHERE t1.rev = (SELECT max(rev) FROM foo t2 WHERE t2.id = t1.id AND t2.rev <= 1)
It might not be the most efficient way to do this, but right now I cannot figure a better way to do this.