I have a time series as follows :
Day. Data 1/1/2020. 0 2/1/2020 .2 3/1/2020 0 ...... ... 1/2/2020 0 2/2/2020. 0 3/2/2020. .2 4/2/2020. .3 5/2/2020. 0 6/2/2020 0 7/2/2020. 0 8/2/2020 2 9/2/2020 2.4 10/2/2020 3
So I want filter data only show after final sequence of zeros that we have in time series in this case I want to get only data after 8/2/202. I have tried this
SELECT * FROM table where Data> 0
here is the result :
Day. Data 2/1/2020 .2 ...... ... 3/2/2020. .2 4/2/2020. .3 8/2/2020 2 9/2/2020 2.4 10/2/2020 3
However this does not find the lates 0 and remove everything before that.
I want also show the result 2 days after the final zero in sequence in the table.
Day Data 10/2/2020 3 11/2/2020. 3.5 ..... ....
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Answer
One method is:
select t.* from t where t.day > (select max(t2.day) from t t2 where t2.value = 0);
You can offset this:
where t.day > (select max(t2.day) + interval '2' day from t t2 where t2.value = 0);
The above assumes that at least one row has zeros. Here are two easy fixes:
where t.day > all (select max(t2.day) from t t2 where t2.value = 0);
or:
where t.day > (select coalesce(max(t2.day), '2000-01-01') from t t2 where t2.value = 0);