Here is my instruction : it works on my friend computer !
CREATE TABLE typeRdv1(
id_type int PRIMARY KEY,
des VARCHAR(20)
);
CREATE TABLE rdv1(
id_rdv int PRIMARY KEY,
cin_pat VARCHAR(20),
date_rdv VARCHAR NOT NULL,
type_rdv VARCHAR(20),
state VARCHAR(20),
CONSTRAINT `FK_cin_rdv` FOREIGN KEY (cin_pat)
REFERENCES patients(cin_pat) ON DELETE NO ACTION,
CONSTRAINT `FK_id_type_rdv` FOREIGN KEY (type_rdv)
REFERENCES typeRdv1(id_type) ON DELETE NO ACTION
);
A ORA-00906: missing left parenthesis
Any help !
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Answer
Please make sure all the “varchar” fields has a length defined. In your second table, it says: date_rdv VARCHAR NOT NULL
, which I believe causing the issue, so try to change it into date_rdv VARCHAR(50) NOT NULL
and try again.
CREATE TABLE rdv1(
id_rdv int PRIMARY KEY,
cin_pat VARCHAR(20),
date_rdv VARCHAR(50) NOT NULL, --length added to varchar
type_rdv VARCHAR(20),
state VARCHAR(20),
EDIT:
The reason you get “invalid character” error is that you cannot use “on delete no action” while creating a table with a constraint. Instead you should alter your table after to create your constraints with “on delete cascade” option. Probably like below ( you may need to drop your constraints first):
CREATE TABLE patients(
cin_pat int PRIMARY KEY,
name VARCHAR(50)
);
CREATE TABLE typeRdv1(
id_type int PRIMARY KEY,
des VARCHAR(20)
);
CREATE TABLE rdv1(
id_rdv int PRIMARY KEY,
cin_pat VARCHAR(20),
date_rdv VARCHAR(50) NOT NULL,
type_rdv VARCHAR(20),
state VARCHAR(20)
);
alter table rdv1 add (
CONSTRAINT FK_cin_rdv FOREIGN KEY (cin_pat)
REFERENCES patients (cin_pat) ON DELETE cascade,
CONSTRAINT FK_id_type_rdv FOREIGN KEY (type_rdv)
REFERENCES typeRdv1 (id_type) ON DELETE cascade
);
Check this for more details: https://www.haidongji.com/2006/07/24/defining-no-action-foreign-key-constraints-in-oracle/comment-page-1/