Hello I’m new to mysqsl and I’m trying to display N/A if the return data is empty or NULL but my query is unrecognized statement type. What do you think is wrong with my query? wrong placement of code?
x
CASE when 'Earliest Time Opened' = '' or 'Earliest Time Opened' is 'Null'
then 'N/A'
ELSE
SELECT (date_format(d.date_opened, '%r') as 'Earliest Time Opened'
FROM daily_report d JOIN userinfo ui
ON d.userid= ui.id
WHERE d.date_opened >= date_sub(curdate(), interval 0 day)
AND d.survey_at_what_blh = 'Bagong Silang' AND ui.status='Employee'
ORDER BY d.date_opened DESC
limit 1
END
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Answer
Use IF
with ISNULL
here:
SELECT IF(ISNULL(d.date_opened), 'N/A', DATE_FORMAT(d.date_opened, '%r')) AS `Earliest Time Opened`
FROM daily_report d
INNER JOIN userinfo ui ON d.userid = ui.id
WHERE
d.date_opened >= CURDATE() AND
d.survey_at_what_blh = 'Bagong Silang' AND
ui.status = 'Employee'
ORDER BY
d.date_opened DESC
LIMIT 1;
If you really wanted to use a CASE
expression, then it would need to appear inside the select clause, something like this:
SELECT CASE WHEN DATE_FORMAT(d.date_opened, '%r') IS NOT NULL
THEN DATE_FORMAT(d.date_opened, '%r')
ELSE 'N/A' END AS `Earliest Time Opened`
But COALESCE
is much more terse and appropriate here.