I got this table:
x
id | score
1 | 1
2 | 4
3 | 4
4 | 3
5 | 2
6 | 2
7 | 1
8 | 4
9 | 2
10 | 3
I need to order it by score desc:
id | score
2 | 4
3 | 4
8 | 4
4 | 3
10 | 3
5 | 2
6 | 2
9 | 2
1 | 1
7 | 1
and get first 3 rows which starts with id
6
So the result should be:
6 | 2
9 | 2
1 | 1
Is this possible? Thanks in advance
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Answer
With this:
select t.*
from tablename t cross join (select * from tablename where id = 6) c
where t.score < c.score or (t.score = c.score and t.id >= c.id)
order by t.score desc, t.id
limit 3
See the demo.
Results:
| id | score |
| --- | ----- |
| 6 | 2 |
| 9 | 2 |
| 1 | 1 |