I am trying to only select one column from 3 distinct phone number columns, and I would prefer to have the column with the longest phone number (some don’t have area codes). Currently, I have coalesced the 3 columns as some are also null, with a preference on cell phone.
Ex.
CREATE TABLE dbo.Persons ( first_name VARCHAR(100) NULL ,cell_number VARCHAR(20) NULL ,home_number VARCHAR(20) NULL ,work_number VARCHAR(20) NULL ); INSERT INTO dbo.Persons ( first_name ,cell_number ,home_number ,work_number ) VALUES ( 'Dave' -- first_name - varchar(100) ,'4567891' -- cell_number - varchar(20) ,'1234567891' -- home_number - varchar(20) ,NULL -- work_number - varchar(20) ) , ( 'Ron' -- first_name - varchar(100) ,'1234567891' -- cell_number - varchar(20) ,NULL -- home_number - varchar(20) ,NULL -- work_number - varchar(20) ) , ( 'Yitzhak' -- first_name - varchar(100) ,'123' -- cell_number - varchar(20) ,NULL -- home_number - varchar(20) ,'1234567891' -- work_number - varchar(20) );
What I’ve tried :
SELECT TOP 1 COALESCE(cell_number, home_number, work_number) FROM Persons ORDER BY LEN(cell_number),LEN(home_number),LEN(work_number) DESC;
I would prefer to just have the first number that is 10 characters long or the longest of the 3 columns, I can only have one column returned. Bonus points if it can keep a preference of cell_number , but not required.
@@version : Microsoft SQL Server 2019 (RTM) – 15.0.2000.5 (X64) Sep 24 2019 13:48:23 Copyright (C) 2019 Microsoft Corporation Express Edition (64-bit) on Windows 10 Enterprise 10.0 (Build 18363: ) (Hypervisor)
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Answer
You can use a case
expression. However, outer apply
is simpler than a big case expression — and generalizes to more phone numbers much more easily:
select p.*, v.phone from persons p outer apply (select top (1) v.phone from (values (cell_number, 1), (home_number, 2), (work_number, 2) ) v(phone, priority) where v.phone is not null order by len(v.phone) desc, priority ) v;