How to insert an existing GUID into Oracle RAW(16) field in a script

I have an sql server script which inserts known fixed guid values into a table. It looks like:

INSERT INTO MyTable (ID)
VALUES ('BBD098BF-58F0-4A84-90C2-F806D6D06061')

Note that guid is in human-readable form. Since ID is uniqueidentifier sql server understands how to convert a string to guid data type.

I need to make the same script for Oracle, ID is of RAW(16) type. Taking the script directly doesn’t work because Oracle interprets a string just like a binary, it should be some “other” string, a string representation of a correct binary chunk.

Does anyone knows a way to convert human-readable sql server string to a string required by Oracle?

So far I can only think about saving a guid to Oracle in .net code, for example, and than making a select in oracle script to get a string. But this is crazy.

Thanks!

Answer

According to this link
Sqlserver reverses the 3 first sections so you need to do:

hextoraw(substr(guid,7,2)||
         substr(guid,5,2)||
         substr(guid,3,2)||
         substr(guid,1,2)||
         substr(guid,12,2)||
         substr(guid,10,2)||
         substr(guid,17,2)||
         substr(guid,15,2)||
         substr(guid,20,4)||
         substr(guid,25,12)
)

(guid is like ‘BBD098BF-58F0-4A84-90C2-F806D6D06061’)