So I want to do something like this sql code below:
select s.id, s.name,s.city from stuff s group by s.name having count(where city and name are identical) > 1
To produce the following, (but ignore where only name or only city match, it has to be on both columns):
id name city 904834 jim London 904835 jim London 90145 Fred Paris 90132 Fred Paris 90133 Fred Paris
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Answer
Duplicated id
for pairs name
and city
:
select s.id, t.* from [stuff] s join ( select name, city, count(*) as qty from [stuff] group by name, city having count(*) > 1 ) t on s.name = t.name and s.city = t.city