I have a table with ids, cities and some sequence number, say:
x
ID CITY SEQ_NO
1 Milan 123
2 Paris 124
1 Rome 125
1 Naples 126
1 Strasbourg 130
3 London 129
3 Manchester 132
2 Strasbourg 128
3 Rome 131
2 Rome 127
4 Moscow 135
5 New York 136
4 Helsinki 137
I want to get the city that comes after Rome for the same id, in this case, I can order them by doing something like:
SELECT ROW_NUMBER() OVER (PARTITION BY ID ORDER BY SEQ_NO) as rownum,
id,
city,
seq_no
FROM mytable
I get:
rownum ID CITY SEQ_NO
1 1 Milan 123
2 1 Rome 125
3 1 Naples 126
4 1 Strasbourg 130
1 2 Paris 124
2 2 Rome 127
3 2 Strasbourg 128
1 3 London 129
2 3 Rome 131
3 3 Manchester 132
1 4 Moscow 135
2 4 Helsinki 137
1 5 New York 136
and, I want to get
ID CITY SEQ_NO
1 Rome 125
1 Naples 126
2 Rome 127
2 Strasbourg 128
3 Rome 131
3 Manchester 132
How do I proceed?
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Answer
Hmmm . . . I might suggest window functions:
select t.*
from (select t.*,
lag(city) over (partition by id order by seq_no) as prev_city
from mytable t
) t
where 'Rome' in (city, prev_city)