CREATE TABLE customers ( id int auto_increment primary key, order_date DATE, customerID VARCHAR(255) ); INSERT INTO customers (order_date, customerID ) VALUES ("2020-01-15", "Customer_01"), ("2020-02-15", "Customer_01"), ("2020-03-18", "Customer_01"), ("2020-04-22", "Customer_01"), ("2021-01-19", "Customer_01"), ("2020-01-25", "Customer_02"), ("2020-02-26", "Customer_02"), ("2020-11-23", "Customer_02"), ("2021-01-17", "Customer_02"), ("2021-02-20", "Customer_02");
Expected Result:
order_date | quantity | (fiscal year) ----------------------------------------------------------------- 2020-01-15 | 1 --> Customer_01 appears the first time between 2019-03 and 2020-02) 2020-01-25 | 1 --> Customer_02 appears the first time between 2019-03 and 2020-02) 2020-02-15 | 0 2020-02-26 | 0 2020-03-18 | 1 --> Customer_01 appears the first time between 2020-03 and 2021-02 2020-04-22 | 0 2020-11-23 | 1 --> Customer_02 appears the first time between 2020-03 and 2021-02 2021-01-17 | 0 2021-01-19 | 0 2021-02-20 | 0
In the above result I want to list all order dates
and count the number of customers
distinct per fiscal year.
The fiscal year
starts two months after the calender year and therefore goes from March
to February
.
(e.g. from 2020-03
til 2021-02
).
For example Customer_01
appears the first time on 2020-03-18
within the fiscal year 2020-03
til 2021-02
.
Therefore, this order_date
gets assigned 1
to it.
If the customer appears again within the fiscal year the next order_date
will get assigned 0
to it.
So far I have used this query:
SELECT order_date, SUM(rn = 1) AS quantity FROM (SELECT order_date, row_number() over(PARTITION BY YEAR(order_date), customerID ORDER BY order_date) rn FROM customers ) t GROUP BY 1;
It works perfectly for the calender year.
However, I have no clue how I can apply the two months shift from the fiscal year to it.
Do you have any idea?
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Answer
I have updated your query as below:
SELECT order_date, SUM(rn = 1) AS quantity FROM (SELECT order_date, row_number() over(PARTITION BY YEAR(order_date - INTERVAL 2 MONTH), customerID ORDER BY order_date) rn FROM customers ) t GROUP BY 1;