x
[Project Numbers]= STUFF((
SELECT ',' + Fin2.[ID]
FROM table Fin2
WHERE In.Investment_Key = Fin2.PROJECT_KEY
FOR XML PATH('')
), 1, 1, '')
I can’t quite figure out how to convert this to snowflake as I am still trying to learn it, is there a STUFF equivalent?
Thanks
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Answer
It is LISTAGG
:
SELECT In.Investment_Key, LISTAGG(Fin2.[ID], ',') AS "Project Numbers"
FROM In
LEFT JOIN table Fin2
ON In.Investment_Key = Fin2.PROJECT_KEY
GROUP BY In.Investment_Key;
STUFF + FOR XML
is an old workaround used for version of SQL Server that does not support STRING_AGG natively. The Snwoflake equivalent is LISTAGG function that could work either as aggregate or windowed function.
Addendum:
The SQL Standard STUFF equivalent is called OVERLAY
with signature as follow:
OVERLAY <left paren> <character value expression>
PLACING <character value expression>
FROM <start position>
[ FOR <string length> ] <right paren>