I have two CTEs that I’ve unioned two produce the following result:
date serie events 2019-05-09 hello 175 2019-05-02 hello 196 2019-05-09 goodbye 1 2019-05-02 goodbye 1
I want to add the events per day together so that
2019-05-09 total 176 2019-05-02 total 197
At the moment I have something like:
with hello_events as ( --- actual logic not interesting --- ) , goodbye_events as ( --- actual logic not interesting --- ) select * from hello_events union all select * from goodbye_events
If I want a third set of results being the sum, I assume I need to do something like
with hello_events as ( --- actual logic not interesting --- ) , goodbye_events as ( --- actual logic not interesting --- ) select * from hello_events union all select * from goodbye_events union all select date, "total", sum(events) as events from hello_events, goodbye_events where hello_events.date = goodbye_events.date
But that’s clearly not correct. What am I missing?
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Answer
Just group by
, as below:
with hello_events as ( --- actual logic not interesting --- ) ,goodbye_events as ( --- actual logic not interesting --- ) ,tmp_result as ( select * from hello_events union all select * from goodbye_events ) select date, 'total', sum(events) from tmp_result group by date