Im having the table with records like below
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO 7369 SMITH CLERK 7902 17-DEC-80 800 - 20 7499 ALLEN SALESMAN 7698 20-FEB-81 1600 300 30 7521 WARD SALESMAN 7698 22-FEB-81 1250 500 30 7566 JONES MANAGER 7839 02-APR-81 2975 - 20 7654 MARTIN SALESMAN 7698 28-SEP-81 1250 1400 30 7698 BLAKE MANAGER 7839 01-MAY-81 2850 - 30 7782 CLARK MANAGER 7839 09-JUN-81 2450 - 10 7788 SCOTT ANALYST 7566 19-APR-87 3000 - 20 7839 KING PRESIDENT - 17-NOV-81 5000 - 10 7844 TURNER SALESMAN 7698 08-SEP-81 1500 0 30 7876 ADAMS CLERK 7788 23-MAY-87 1100 - 20 7900 JAMES CLERK 7698 03-DEC-81 950 - 30 7902 FORD ANALYST 7566 03-DEC-81 3000 - 20 7934 MILLER CLERK 7782 23-JAN-82 1300 - 10
and i need to get the manager details where the all the employees under the manager should have salary more than 1000
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Answer
Here is a solution that uses a correlated subquery:
select e.* from emp e where (select min(e1.sal) from emp e1 where e1.mgr = e.empno) >= 1000
This ensures that:
- the selected employee is a manager (ie they manage at least one employee)
- all of the managees of the manager have a salary above (or equal to) 1000