postgres Finding the difference between numbers of…

I have a table like the below

| date       | key | value |   |
|------------|-----|-------|---|
| 01-01-2009 | a   | 25    |   |
| 01-01-2009  | b   | 25    |   |
| 01-01-2009  | c   | 10    |   |

I’m trying to come up with a query which would allow me to do (a+b)-c for each day – but my join is doing this (a+b+c)-c

with total as (
select
    sum(value),
    date
from
    A
where
    key in ('a',
    'b')
group by
    date ) 
select
    sum(total.sum) as a, sum(A.value) as b,
    sum(total.sum) - sum(A.value) as value,
        A.date
    from
        A
    join total on
        total.date = A.date
    where
        A.key = 'c'
    group by
        A.date

This is giving me a value of 50 (it should be 40) – my C values are getting calcualted as part of the total table during the join

What am i doing wrong?

Answer

How about simply doing conditional aggregation?

select date,
       sum(case when key in ('a', 'b') then value 
                when key in ('c') then - value
           end) as daily_calc
from a
group by date;

A join doesn’t seem very helpful for this calculation.

postgres Finding the difference between numbers of the same column

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Answer