I would like to include null values in an Apache Spark join. Spark doesn’t include rows with null by default.
Here is the default Spark behavior.
val numbersDf = Seq(
("123"),
("456"),
(null),
("")
).toDF("numbers")
val lettersDf = Seq(
("123", "abc"),
("456", "def"),
(null, "zzz"),
("", "hhh")
).toDF("numbers", "letters")
val joinedDf = numbersDf.join(lettersDf, Seq("numbers"))
Here is the output of joinedDf.show():
+-------+-------+ |numbers|letters| +-------+-------+ | 123| abc| | 456| def| | | hhh| +-------+-------+
This is the output I would like:
+-------+-------+ |numbers|letters| +-------+-------+ | 123| abc| | 456| def| | | hhh| | null| zzz| +-------+-------+
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Answer
Spark provides a special NULL safe equality operator:
numbersDf
.join(lettersDf, numbersDf("numbers") <=> lettersDf("numbers"))
.drop(lettersDf("numbers"))
+-------+-------+ |numbers|letters| +-------+-------+ | 123| abc| | 456| def| | null| zzz| | | hhh| +-------+-------+
Be careful not to use it with Spark 1.5 or earlier. Prior to Spark 1.6 it required a Cartesian product (SPARK-11111 – Fast null-safe join).
In Spark 2.3.0 or later you can use Column.eqNullSafe in PySpark:
numbers_df = sc.parallelize([
("123", ), ("456", ), (None, ), ("", )
]).toDF(["numbers"])
letters_df = sc.parallelize([
("123", "abc"), ("456", "def"), (None, "zzz"), ("", "hhh")
]).toDF(["numbers", "letters"])
numbers_df.join(letters_df, numbers_df.numbers.eqNullSafe(letters_df.numbers))
+-------+-------+-------+ |numbers|numbers|letters| +-------+-------+-------+ | 456| 456| def| | null| null| zzz| | | | hhh| | 123| 123| abc| +-------+-------+-------+
and %<=>% in SparkR:
numbers_df <- createDataFrame(data.frame(numbers = c("123", "456", NA, "")))
letters_df <- createDataFrame(data.frame(
numbers = c("123", "456", NA, ""),
letters = c("abc", "def", "zzz", "hhh")
))
head(join(numbers_df, letters_df, numbers_df$numbers %<=>% letters_df$numbers))
numbers numbers letters 1 456 456 def 2 <NA> <NA> zzz 3 hhh 4 123 123 abc
With SQL (Spark 2.2.0+) you can use IS NOT DISTINCT FROM:
SELECT * FROM numbers JOIN letters ON numbers.numbers IS NOT DISTINCT FROM letters.numbers
This is can be used with DataFrame API as well:
numbersDf.alias("numbers")
.join(lettersDf.alias("letters"))
.where("numbers.numbers IS NOT DISTINCT FROM letters.numbers")