I have a table with many columns, and I want to count the unique values of each column. I know that I can do
SELECT sho_01, COUNT(*) from sho GROUP BY sho_01 UNION ALL SELECT sho_02, COUNT(*) from sho GROUP BY sho_02 UNION ALL ....
Here sho
is the table and sho_01
,…. are the individual columns. This is BigQuery by the way, so they use UNION ALL
.
Next, I want to do the same thing, but for a subset of sho
, say SELECT * FROM sho WHERE id in (1,2,3)
. Is there a way where I can create a subtable first, and then query the subtable? Something like this
SELECT * FROM (SELECT * FROM sho WHERE id IN (1,2,3)) AS t1; SELECT sho_01, COUNT(*) from t1 GROUP BY sho_01 UNION ALL SELECT sho_02, COUNT(*) from t1 GROUP BY sho_02 UNION ALL ....
Thanks
Advertisement
Answer
Presumably, the columns are all of the same type. If so, you can simplify this using arrays:
select el.which, el.val, count(*) from (select t1.*, array[struct('sho_01' as which, sho_01 as val), struct('sho_2', show_02), . . . ] as ar from t ) t cross join unnest(ar) el group by el.which, el.val;
You can then easily filter however you want by adding a where
clause before the group by
.