I have a large table that I need to re-sort periodically. I am partly basing this on a suggestion I was given to stay away from using cluster keys since I am inserting data ordered differently (by time) from how I need it clustered (by ID), and that can cause re-clustering to get a little out of control. Since I
Amazon Athena returning “mismatched input ‘partitioned’ expecting {, ‘with’}” error when creating partitions
I’d like to use this query to create a partitioned table in Amazon Athena: Unfortunately I don’t get the error message which tells me the following: line 3:2: mismatched input ‘partitioned’ expecting {, ‘with’} Answer The quotes around ‘PARQUET’ seemed to be causing a problem. Try this:
How to bind variable in string in SQL query?
I am using SQL Developer. When I want to bind value. Normally I use following syntax: but, I don’t know how to do that in string. The following query does not work. Why do I need it? Because my program runs a query in python and assigns something to bind variable: Answer Concatenate the prefix/suffix with the bind variable:
date time comparison with > does not work
I have two SQL statements: 1) (now i use this) 2) (but i need to use this) first query return 11 lines query 2 return 388. my observation (about query 2) is that instead of “2019-11-26 13:20:00” it is taken “2019-11-26” and when I replace it really returns the same answer date_occured is of type of timestamp without time zone
Count double occurrences in order list
I have a list of orders, I need to find which ones occur with code 47 more than once with different users. For example: The expected result is 111 and 333. How can I accomplish this? Regards Answer I think you want aggregation and having: You can also express the having as:
How to identity customer orders by customer IDs [closed]
Closed. This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 2 years ago. Improve this question Say for example I have table Customer and I have another table called orders. How to identify that each order belongs to that particular customer.
MYSQL Query calculate percentage of emails not null
I have these two queries. Caluculates count of emails that are null SELECT COUNT(*) as invalid_email FROM distinct_customers WHERE c_email IS NULL; Calculates count of every email SELECT COUNT(distinct c_number) as total FROM distinct_customers; I am trying to combine those to queries so that it gives me a percentage of valid emails (not null) I tried a couple of ways
SQL query to get all data for a particular user
I have two tables: Users (idk, surnamek, namek, logink), Measurements (idm, date, weight, #idk) I need to create a query to get all measurements for a particular logink. Answer use inner join:
Correction Needed for error in Oracle query
I want calculate the all students credit hours separately group by stduents of each? needed help to correction of query Answer Try this:
Select unmatched records from two tables with a filter on second table
I have 2 mysql tables a and b. I need to show all records in a that are not in b using a common column ‘ID’. Normally this is pretty straight forward but my problem here is this: I need to put a where clause on table b because I’m not interested in all unmatched records just the ones that